Home
Class 12
CHEMISTRY
1g of the carbonate of a metal was diss...

`1g` of the carbonate of a metal was dissolved in `25mL` of `N-HCl`. The resulting liquid required `5 mL` of `N-NaOH` for neutralisation. The `Ew` of the metal Carbonate is

A

50

B

30

C

20

D

40

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPT OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise ENABLE|49 Videos
  • SOME BASIC CONCEPT OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise EFFICIENT|50 Videos
  • REVISION TEST-2 JEE

    VMC MODULES ENGLISH|Exercise CHEMISTRY|25 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    VMC MODULES ENGLISH|Exercise IN - CHAPTER EXERCISE - H|8 Videos

Similar Questions

Explore conceptually related problems

1g of the carbonate of a metal was dissolved in 25mL of N-HCl . Te resulting liquid 5 mL of N-NaOH for neutralisation. The Ew of the metal Carbonate is

4.08 g of a mixture of BaO and an unknown carbonate MCO_(3) was heated strongly. The residue weighed 3.64 g . This was dissolved in 100 mL of 1 N HCl . The excess of acid required of 16 mL of 2.5 N NaOH for complete neutralisation. Identify the matal M .

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

0.303 g of an organic compound was analysed for nitrogen by Kjeldahl's method. The ammonia evolved was absorbed in 50 ml of 0.1 N H_2 SO_4 . The excess acid required 25 ml of 0.1 N NaOH for neutralisation. Calculate the percentage of nitrogen in the compound.

1.250 g of metal carbonate (MCO_(3)) was treated with 500 mL of 0.1 M HCl solution. The unreacted HCl required 50.0 mL of 0.500 M NaOH solution for neutralization, Identify the metal M

7.5 g of an acid are dissolved per litre of the solution. 20 mL of this acid solution required 25 mL of N//15 NaOH solution for complete neutralization. Calculate the equivalent mass of the acid.

0.16 g of dibasic acid required 25 ml of decinormal NaOH solution for complete neutralisation. The molecular weight of the acid will be

0.84 g of a acid (mol wt. 150) was dissolved in water and the volume was made up to 100 ml. 25 ml of this solution required 28 ml of (N/10) NaOH solution for neutralisation. The equivalent weight and basicity of the acid

0.16 gm of a dibasic organic acid required 25.0 ml of (N)/(10)NaOH for complete neutralisation. Calculate its molucular mass.

0.075 g of a monobasic acid required 10 mL of N//12 NaOH solution for complete neutralisation. Calculate the molecular mass of the acid

VMC MODULES ENGLISH-SOME BASIC CONCEPT OF CHEMISTRY-IMPECCABLE
  1. 1g of the carbonate of a metal was dissolved in 25mL of N-HCl. The re...

    Text Solution

    |

  2. How many moles of lead (II) chloride will be formed from a reaction be...

    Text Solution

    |

  3. What is the volume of one molecules of water (density of H(2) O = 1 g ...

    Text Solution

    |

  4. An organic compound contains carbon , hydrogen and oxygen . Its elemen...

    Text Solution

    |

  5. What volume of oxygen gas (O(2)) measured at 0^(@)C and 1 atm , is ne...

    Text Solution

    |

  6. During electrolysis of water, the volume of oxygen liberated is 2.24 d...

    Text Solution

    |

  7. Number of moles of MnO(4)^(-) required to oxidise one mole of ferrous ...

    Text Solution

    |

  8. 10 g of hydrogen and 64 g of oxygen were filled in a steel vessel and ...

    Text Solution

    |

  9. A bivalent metal has an equivalent mass of 32. The molecular mass of t...

    Text Solution

    |

  10. The number of significant figures is 10.3406 g in :

    Text Solution

    |

  11. 1.5g CdCl(2) was formed to contain 0.9g Cd. Calculate the atmic weight...

    Text Solution

    |

  12. The volume of 2N H(2)SO(4) solution is 0.1dm^(3). The volume of its de...

    Text Solution

    |

  13. what volume of CO2 will be liberated at STP if 12 g of carbon is burnt...

    Text Solution

    |

  14. The equivalent mass of MnSO4 is half of its molecular mass when it is ...

    Text Solution

    |

  15. x moles of potassium dichromate oxidizes 1 mole of ferrous oxalate in ...

    Text Solution

    |

  16. Express of CO(2) is passed through 50 mL of 0.5 M calcium hydroxide so...

    Text Solution

    |

  17. The number of electrons required to reduce 4.5 xx 10^(–5) g of Al^(+3)...

    Text Solution

    |

  18. How much volume of oxygen at STP in litres is required to burn 4g of m...

    Text Solution

    |

  19. Equivalent weight of Potassiumpermaganate in strong alkaline medium is

    Text Solution

    |

  20. An organic compound contains 40%C, 6.6%H. The empirical formula of the...

    Text Solution

    |

  21. 1 u (amu) is equal to

    Text Solution

    |