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Among the following the strongest base i...

Among the following the strongest base is

A

`C_(6)H_(5)NH_(2)`

B

`p-NO_(2)-C_(6)H_(4)NH_(2)`

C

`m-NO_(2)-C_(6)H_(4)NH_(2)`

D

`C_(6)H_(5)CH_(2)NH_(2)`

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The correct Answer is:
To determine which of the given compounds is the strongest base among the options, we will analyze the basicity of each compound based on the presence of electron-donating and electron-withdrawing groups. ### Step-by-Step Solution: 1. **Identify the Compounds**: - The compounds given are: 1. Aniline (C6H5NH2) 2. Para-nitroaniline (C6H4(NO2)NH2) 3. Meta-nitroaniline (C6H4(NO2)NH2) 4. Benzylamine (C6H5CH2NH2) 2. **Understand Basicity in Amines**: - Basicity in amines is primarily due to the lone pair of electrons on the nitrogen atom. The availability of this lone pair for protonation determines the basic strength. - Electron-donating groups (EDGs) increase basicity by increasing electron density on nitrogen, while electron-withdrawing groups (EWGs) decrease basicity by reducing electron density. 3. **Analyze Each Compound**: - **Aniline (C6H5NH2)**: The lone pair on nitrogen is partially delocalized into the benzene ring due to resonance, which reduces its availability for protonation. Therefore, it is less basic. - **Para-nitroaniline (C6H4(NO2)NH2)**: The nitro group (-NO2) is a strong electron-withdrawing group. Its presence at the para position further decreases the basicity of the amine compared to aniline. - **Meta-nitroaniline (C6H4(NO2)NH2)**: Similar to para-nitroaniline, the nitro group at the meta position also withdraws electron density, making it less basic than aniline. - **Benzylamine (C6H5CH2NH2)**: The amine group is not directly attached to the benzene ring, so the lone pair on nitrogen is more available for protonation. Additionally, the benzyl group can exhibit some electron-donating character, enhancing the basicity. 4. **Compare Basicity**: - Among the compounds analyzed: - Aniline is less basic than benzylamine due to resonance. - Para-nitroaniline and meta-nitroaniline are even less basic than aniline due to the strong electron-withdrawing effect of the nitro group. - Benzylamine has the highest basicity because the lone pair on nitrogen is more available for protonation. 5. **Conclusion**: - Based on the analysis, the strongest base among the given options is **Benzylamine (C6H5CH2NH2)**. ### Final Answer: The strongest base among the given options is **Benzylamine (C6H5CH2NH2)**.
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VMC MODULES ENGLISH-AMINES-IMPECCABLE
  1. which of the indicated 'H' is most acidic ?

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  2. Correct order of acidic strength in following acids will be:

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  3. The magor product formed in the elimination reaction of is:

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  4. When CH(3)CH(2) CHCl(2) is treated with "NaNH"(2) , the product formed...

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  5. Which of the following is not the metamer of CH3CH2-underset(CH3)under...

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  6. Which of the following compound is most acidic?

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  7. Which one of the following amines is the weakest base?

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  8. Among the following the strongest base is

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  9. Which of the following compounds is most basics

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  10. Describe the following giving the relevant chemical equation in each ...

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  11. In the Sandmeyer's reaction, -NH-X group of diazonium salt is replaced...

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  12. Reaction of benzenediazonium chloride with alkaline b - napthol gives ...

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  13. The minimum value of -logK(b) will be for the compound

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  14. The reagents that can be used to convert benzenediazonium chloride to ...

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  15. Acetanilide when treated with bromine in acetic acid gives:

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  16. Which reagent is used to get iodo benzene from benzene diazonium acid ...

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  17. The correct order of base strength of substituted aniline is

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  18. Choose the false statement

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  19. Of the following statements: (a) C(6)H(5)N=CH-C(6)H(5) is a Schiff's...

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  20. I overset(COCl2) larr "Aniline"overset(C2 H5 MgI)to II. Products I an...

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