`I overset(COCl_2) larr "Aniline"overset(C_2 H_5 MgI)to II`. Products I and II are :

Options

A. Diphenylurea , ehtane
B. Diphenylurea ,` C_6H_5MgI`
C. Dipphenlamine , ethane
D. Diphenylamine , benzene

Answer

To solve the question, we need to identify the products formed when aniline reacts with phosgene (COCl₂) and when it reacts with the Grignard reagent (C₂H₅MgI).

### Step 1: Reaction of Aniline with Phosgene (COCl₂)

1. **Identify the reactants**: We have aniline (C₆H₅NH₂) and phosgene (COCl₂).
2. **Mechanism of reaction**:
- The carbonyl carbon in phosgene is electrophilic due to the presence of the electronegative oxygen.
- The nitrogen atom in aniline, which has a lone pair of electrons, attacks the electrophilic carbon of phosgene.
- This leads to the formation of an intermediate where the chlorine atom is displaced.
3. **Formation of the product**:
- The intermediate can further react with another molecule of aniline, leading to the formation of a compound known as 1,3-diphenylurea.
- The final product can be represented as:
\[ \text{C}_6\text{H}_5\text{N}(\text{C}=O)\text{N}(\text{C}_6\text{H}_5) \quad \text{(1,3-diphenylurea)} \]

### Step 2: Reaction of Aniline with Grignard Reagent (C₂H₅MgI)

1. **Identify the reactants**: Aniline (C₆H₅NH₂) and the Grignard reagent (C₂H₅MgI).
2. **Mechanism of reaction**:
- The carbon in the Grignard reagent (C₂H₅MgI) acts as a nucleophile and can react with the acidic hydrogen of the amine group in aniline.
- The Grignard reagent will abstract the hydrogen from the amine, forming ethane (C₂H₆) and a new compound where the nitrogen is bonded to the magnesium halide (MgI).
3. **Formation of the product**:
- The reaction leads to the formation of a compound represented as:
\[ \text{C}_6\text{H}_5\text{N}(\text{MgI}) + \text{C}_2\text{H}_6 \quad \text{(with ethane as a byproduct)} \]

### Summary of Products

- **Product I** (from aniline + phosgene): 1,3-diphenylurea
- **Product II** (from aniline + C₂H₅MgI): Ethane (C₂H₆)

### Final Answer

- **Product I**: 1,3-diphenylurea
- **Product II**: Ethane (C₂H₆)

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