Home
Class 12
CHEMISTRY
For a hydrogen atom, the energies that a...

For a hydrogen atom, the energies that an electron can have are given by the expression, `E=-13.58//n^(2)eV`, where n is an integer. The smallest amount of energy that a hydrogen atom in the ground state can absorb is:

A

1.00 eV

B

3.39 eV

C

1.79 eV

D

10.19 eV

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise ENABLE|50 Videos
  • STRUCTURE OF ATOM

    VMC MODULES ENGLISH|Exercise EFFICIENT|48 Videos
  • STOICHIOMETRY-II

    VMC MODULES ENGLISH|Exercise JEE Advanced (Archive)|43 Videos
  • SURFACE CHEMISTRY

    VMC MODULES ENGLISH|Exercise PRACTICE EXERCISE|9 Videos

Similar Questions

Explore conceptually related problems

The energy of the electron in the hydrogen atom is given by the expression

An electron with kinetic energy 5eV is incident on a hydrogen atom in its ground state.The collision

An electron with kinetic energy 5eV is incident on a hydrogen atom in its ground state.The collision

If the energy in the first excited state in hydrogen atom is 23.8 eV then the potential energy of a hydrogen atom in the ground state can be assumed to be

An electron with kinetic energy 10 eV is incident on a hydrogen atom in its ground state. The collision

In a hydrogen atom, if energy of an electron in ground state is - 13.6 eV , then that in the 2^(nd) excited state is :

Calculate the frequency in s^(-1) of infrated photons that can be absorbed by HD molecule. (If you have been unable to calculate the value for epsilon_(HD) then use 8.000xx10^(-20) the calculation) The allowed electronic energies of H atom of H atom are given by the expression: E=-R_(H)/n^(2), n=1, 2, .... where R_(H)=13.5984 eV and 1 eV=1.602xx10^(-19) J The total energy of H_(2) molecules in its ground state is -31.675 eV , relative to the same refrence as that of hydrogen atom.

When an electron in the hydrogen atom in ground state absorb a photon of energy 12.1eV , its angular momentum

Hydrogen atom: The electronic ground state of hydrogen atom contains one electron in the first orbit. If sufficient energy is provided, this electron can be promoted to higher energy levels. The electronic energy of a hydrogen-like species (any atom//ions with nuclear charge Z and one electron) can be given as E_(n)=-(R_(H)Z^(2))/(n^(2)) where R_(H)= "Rydberg constant," n= "principal quantum number" The ratio of energy of an electron in the ground state Be^(3-) ion to that of ground state H atom is: The kinetic and potential energies of an electron in the H atoms are given as K.E. =e^(2)/(4 pi epsilon_(0)2r) and P.E.=-1/(4pi epsilon_(0)) e^(2)/r

In a hydrogen atom , If the energy of electron in the ground state is -x eV ., then that in the 2^(nd) excited state of He^(+) is