If wavelength of photon is `2.2 xx 10^(-11)m`, `h = 6.6 xx 10^(-34) Js`, then momentum of photons is

Options

A. `3.0xx10^(-23) kgm sec^(-1)`
B. `3.3 xx10^(22) kgm sec^(-1)`
C. `1.45 xx10^(-44) kgm sec^(-1)`
D. `6.89 xx10^(-43) kgm sec^(-1)`

Answer

To find the momentum of a photon given its wavelength, we can use the de Broglie equation, which relates the wavelength of a particle to its momentum. The equation is given by:

\[ \lambda = \frac{h}{p} \]

Where:
- \(\lambda\) is the wavelength,
- \(h\) is Planck's constant,
- \(p\) is the momentum.

We can rearrange this equation to solve for momentum \(p\):

\[ p = \frac{h}{\lambda} \]

### Step-by-Step Solution:

1. **Identify the given values:**
- Wavelength (\(\lambda\)) = \(2.2 \times 10^{-11} \, m\)
- Planck's constant (\(h\)) = \(6.6 \times 10^{-34} \, Js\)

2. **Substitute the values into the momentum formula:**
\[ p = \frac{h}{\lambda} = \frac{6.6 \times 10^{-34} \, Js}{2.2 \times 10^{-11} \, m} \]

3. **Perform the division:**
- First, divide the coefficients:
\[ \frac{6.6}{2.2} = 3 \]
- Next, divide the powers of ten:
\[ \frac{10^{-34}}{10^{-11}} = 10^{-34 + 11} = 10^{-23} \]

4. **Combine the results:**
\[ p = 3 \times 10^{-23} \, kg \cdot m/s \]

5. **Final result:**
The momentum of the photon is:
\[ p = 3.0 \times 10^{-23} \, kg \cdot m/s \]

### Conclusion:
Thus, the momentum of the photon is \(3.0 \times 10^{-23} \, kg \cdot m/s\).