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The wavelengths of electron waves in two...

The wavelengths of electron waves in two orbits is 3:5. The ratio of kinetic energy of electrons will be

A

`25:9`

B

`5:3`

C

`9:25`

D

`3:5`

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To solve the problem of finding the ratio of kinetic energy of electrons based on the given wavelengths in two orbits, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Wavelength Ratio**: We are given that the wavelengths of electron waves in two orbits are in the ratio of 3:5. Let's denote the wavelengths as: \[ \lambda_1 = 3x \quad \text{and} \quad \lambda_2 = 5x \] 2. **Using the Wavelength Formula**: The wavelength of an electron can be expressed using the formula: \[ \lambda = \frac{h}{\sqrt{2mk}} \] where \( h \) is Planck's constant, \( m \) is the mass of the electron, and \( k \) is the kinetic energy of the electron. 3. **Setting Up the Proportionality**: Since the wavelength is inversely proportional to the square root of the kinetic energy, we can write: \[ \frac{\lambda_1}{\lambda_2} = \frac{\sqrt{k_2}}{\sqrt{k_1}} \] 4. **Substituting the Wavelengths**: Substituting the values of \( \lambda_1 \) and \( \lambda_2 \): \[ \frac{3x}{5x} = \frac{\sqrt{k_2}}{\sqrt{k_1}} \] Simplifying this gives: \[ \frac{3}{5} = \frac{\sqrt{k_2}}{\sqrt{k_1}} \] 5. **Squaring Both Sides**: To eliminate the square roots, we square both sides: \[ \left(\frac{3}{5}\right)^2 = \frac{k_2}{k_1} \] This results in: \[ \frac{9}{25} = \frac{k_2}{k_1} \] 6. **Finding the Ratio of Kinetic Energies**: We need to find the ratio \( \frac{k_1}{k_2} \): \[ \frac{k_1}{k_2} = \frac{25}{9} \] Thus, the ratio of the kinetic energies \( k_1 : k_2 \) is: \[ k_1 : k_2 = 25 : 9 \] 7. **Conclusion**: Therefore, the ratio of the kinetic energy of electrons in the two orbits is \( 25 : 9 \).
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