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The set of quantum number for the 19^(th...

The set of quantum number for the `19^(th)` electrons in chromium is -

A

`4,0,0,1/2`

B

`4,1,-1,1/2`

C

`3,2,2,1/2`

D

`3,2,-2,1/2`

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The correct Answer is:
To find the set of quantum numbers for the 19th electron in chromium (Cr), we will follow these steps: ### Step 1: Determine the Atomic Number of Chromium Chromium has an atomic number of 24, which means it has 24 electrons. ### Step 2: Write the Electron Configuration The electron configuration for chromium is: \[ \text{Cr: } 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5 \] ### Step 3: Identify the 19th Electron To find the 19th electron, we will count the electrons in the configuration: - 1s: 2 electrons - 2s: 2 electrons - 2p: 6 electrons - 3s: 2 electrons - 3p: 6 electrons - 4s: 1 electron - 3d: 5 electrons Adding these: \[ 2 + 2 + 6 + 2 + 6 + 1 = 19 \] Thus, the 19th electron is in the 4s subshell. ### Step 4: Determine the Quantum Numbers The quantum numbers consist of: 1. Principal quantum number (n) 2. Azimuthal quantum number (l) 3. Magnetic quantum number (m_l) 4. Spin quantum number (m_s) For the 4s subshell: - **Principal quantum number (n)**: For the 4s subshell, \( n = 4 \). - **Azimuthal quantum number (l)**: For s orbitals, \( l = 0 \). - **Magnetic quantum number (m_l)**: Since \( l = 0 \), \( m_l = 0 \). - **Spin quantum number (m_s)**: The first electron in the 4s subshell will have a spin of \( +\frac{1}{2} \) (clockwise). ### Step 5: Compile the Quantum Numbers Thus, the set of quantum numbers for the 19th electron in chromium is: \[ (n, l, m_l, m_s) = (4, 0, 0, +\frac{1}{2}) \] ### Final Answer The set of quantum numbers for the 19th electron in chromium is: \[ \boxed{(4, 0, 0, +\frac{1}{2})} \] ---
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