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When the electron of a hydrogen atom jum...

When the electron of a hydrogen atom jumps from the n=4 to the n=1 state , the number of all pos - sible spectral lines emitted is :-

A

15

B

9

C

6

D

3

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The correct Answer is:
To solve the problem of determining the number of possible spectral lines emitted when an electron in a hydrogen atom jumps from the n=4 state to the n=1 state, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Initial and Final States**: - The initial state (n2) is 4. - The final state (n1) is 1. 2. **Use the Formula for Spectral Lines**: - The formula to calculate the number of spectral lines emitted when an electron transitions between two energy levels is given by: \[ \text{Number of spectral lines} = \frac{(n_2 - n_1)(n_2 - n_1 + 1)}{2} \] 3. **Substitute the Values into the Formula**: - Here, \(n_2 = 4\) and \(n_1 = 1\). - Calculate \(n_2 - n_1\): \[ n_2 - n_1 = 4 - 1 = 3 \] - Now substitute into the formula: \[ \text{Number of spectral lines} = \frac{(3)(3 + 1)}{2} \] 4. **Calculate the Number of Spectral Lines**: - Simplifying the expression: \[ \text{Number of spectral lines} = \frac{(3)(4)}{2} = \frac{12}{2} = 6 \] 5. **Conclusion**: - Therefore, the number of possible spectral lines emitted when the electron jumps from n=4 to n=1 is **6**. ### Final Answer: The number of all possible spectral lines emitted is **6**. ---
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