The dissociation of `I_(2) overset(hv)rarr 2I` utilizes one photon per iodine molecule dissociated. The maximum `lamda` for this is `4995 Å`. Calculate the number of moles of `I_(2)` dissociated per kJ of photon energy?

Explanation

To solve the problem of calculating the number of moles of \( I_2 \) dissociated per kJ of photon energy, we will follow these steps:

### Step 1: Convert the wavelength from angstroms to meters
The given wavelength \( \lambda \) is \( 4995 \, \text{Å} \). We know that:
\[ 1 \, \text{Å} = 10^{-10} \, \text{m} \]
Thus,
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