The energy of the electron in the second and third Bohr's orbitals of the hydrogen atom is `-5.42 xx 10^(-12) erg` and `-2.42 xx 10^(-12) erg` respectively ,Calculate the wavelength of the emitted radiation when the electron drops from the third to the second orbit.

Explanation

To solve the problem of calculating the wavelength of the emitted radiation when an electron drops from the third to the second Bohr orbital in a hydrogen atom, we can follow these steps:

### Step 1: Identify the energies of the orbits
The energy of the electron in the second orbital (n=2) is given as:
\[ E_2 = -5.42 \times 10^{-12} \text{ erg} \]

The energy of the electron in the third orbital (n=3) is given as:
\[ E_3 = -2.42 \times 10^{-12} \text{ erg} \]
...