Two particles A and B are in motion . IF the wavelength associtated with particle A is `5xx 10^(-8) m,` calculate the wavelength associated with particle B if its momentum is half of A.

Explanation

`lamda_(A) = (h)/(p) and lamda_(B) = (h)/(p//2)`. So, dividing the two equations we get, `(lamda_(A))/(lamda_(B)) = (5 xx 10^(-8)m)/(lamda_(B)) = (1)/(2)` That is, `lamda_(B) = 10^(-7) m`