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If uncertainty in position and velocity are equal the uncertainty in momentum will be

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To solve the problem of finding the uncertainty in momentum when the uncertainty in position (Δx) and uncertainty in velocity (Δv) are equal, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Heisenberg Uncertainty Principle**: The Heisenberg Uncertainty Principle states that the product of the uncertainties in position and momentum is always greater than or equal to a constant value. Mathematically, it is expressed as: \[ \Delta x \cdot \Delta p \geq \frac{h}{4\pi} ...
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If uncertainty in position and momentum are equal then uncertainty in velocity is.

It is not possible to determine precisely both the position and momentum (or velocity) of a small moving particle such as electron, proton etc. This is known as Heisenberg uncertainty principle. The mathematical form of this principle is : Delta x.Delta p ge (h)/(4pi) (constant) However this principle is irrelevant in case of bigger particles such as a cup, ball, car etc., that we come across in our daily life. If uncertainty in position and momentum are equal, the v uncertainty in velocity would be

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainty in velocity and position is same, then the uncertainty in momentum will be :

If the uncertainties in position and momentum are equal, the uncertainty in the velocity is :

If the uncertainty in the position of an electron is zero the uncertainty in its momentum be

If the uncertainty in the position of an electron is zero the uncertainty in its momentum be

Werner Heisenberg considered the limits of how precisely we can measure the properties of an electron or other microscopic particle. He determined that there is a fundamental limit to how closely we can measure both position and momentum. The more accurately we measure the momentum of a particle, the less accurately we can determine its position. The converse also true. This is summed up in what we now call the Heisenberg uncertainty principle. The equation si deltax.delta (mv)ge(h)/(4pi) The uncertainty in the position or in the momentum of a marcroscopic object like a baseball is too small to observe. However, the mass of microscopic object such as an electon is small enough for the uncertainty to be relatively large and significant. If the uncertainties in position and momentum are equal, the uncertainty in the velocity is :

It is not possible to determine precisely both the position and momentum (or velocity) of a small moving particle such as electron, proton etc. This is known as Heisenberg uncertainty principle. The mathematical form of this principle is : Delta x.Delta p ge (h)/(4pi) (constant) However this principle is irrelevant in case of bigger particles such as a cup, ball, car etc., that we come across in our daily life. If the uncertainty in position of the electron is zero, the uncertainty in its momentum would be

If uncertainty in position is twice the uncertainty in momentum then uncertainty in velocity is

What is the minimum product of the uncertainty in position and the uncertainty in momentum of a moving electron ?

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