The ionzation energy of the electron is the lowest orbit of hydrogen atom is `13.6 eV` . The energies required in eV . To remove electron from three lowest orbits of hydrogen atom are

Options

A. `13.6, 6.8, 8.4`
B. `13.6,10.2, 3.4`
C. `13.6, 27.2, 40.8`
D. `13.6, 3.4, 1.51`

Answer

D

Explanation

Removal of electron refers to knocking off the electron upto infinity. The energy required in such cases
`Delta E = 13.6 ((1)/(n_(1)^(2)) - (1)/(oo^(2))) xx Z^(2) = 13.6 ((1)/(n_(1)^(2)))xx Z^(2) eV`. For `2^(nd)` shell `-13.6//4 = 3.4eV and 3^(rd) " shell "=-13.6//9= -1.51 eV`