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Find out the calorific value of Glucose ...

Find out the calorific value of Glucose `C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900` kJ/mole

A

33.2 kJ/g

B

16.1 kJ/g

C

13.8 kJ/g

D

9.1 kJ/g

Text Solution

Verified by Experts

Heat produced from 1 mole of `C_(6)H_(12)O_(6)(180 gm) = 2900 kJ, " "` Heat produced from 1 gm glucose `=(2900)/(180)=16.1` kJ/gm
So, calorific value of `C_(6)H_(12)O_(6)` is 16.1 kJ/gm
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