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48 g of C(diamond) on complete combustio...

48 g of C(diamond) on complete combustion evolves 1584 kJ of heat. The standard heat of formation of gaseous carbon is 725 kJ/mol. The energy required for the process.
(i) C(graphite) +O`to` C(gas) `" "` (ii) C(diamond) + `to` C(gas) are Given : `C("diamond") to C("graphite"), Delta H = -2 kJ //mol`.

A

725, 727

B

727, 725

C

725, 723

D

725, 729

Text Solution

Verified by Experts

The expression for standard heat of formation of gaseous carbon is
C (graphite) `rarr` C (gas)
`Delta_(f)H^(@)=725` kJ/mol
As graphite is thermodynamically more stable than diamond so the heat required to convert graphite to gaseous carbon should be more.
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