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When 50 cm^(3) of a strong acid is added...

When `50 cm^(3)` of a strong acid is added to of an alkali, the temperature rises by `5^(@)C`. If `250 cm^(3)` of each liquid are mixed, the temperature rise would be

A

`5^(@)C`

B

`10^(@)C`

C

`25^(@)C`

D

`20^(@)C`

Text Solution

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The correct Answer is:
To solve the problem, we need to understand the concept of heat of neutralization and how it relates to the temperature change when mixing a strong acid and a strong base. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We are given that when 50 cm³ of a strong acid is mixed with an alkali, the temperature rises by 5°C. - We need to determine the temperature rise when 250 cm³ of each liquid (strong acid and strong base) are mixed. 2. **Heat of Neutralization**: - The heat of neutralization for a strong acid and a strong base is constant. This means that regardless of the volumes of the acid and base, the amount of heat released during the neutralization reaction remains the same. 3. **Temperature Rise with Equal Volumes**: - When 50 cm³ of strong acid is mixed with 50 cm³ of strong base, the temperature rise is 5°C. This is the result of the heat released during the neutralization reaction. 4. **Scaling Up the Volumes**: - If we mix 250 cm³ of strong acid with 250 cm³ of strong base, we are effectively increasing the volume of both reactants by a factor of 5 (since 250 cm³ is 5 times 50 cm³). - However, the temperature rise does not depend on the volume of the reactants when dealing with strong acids and bases. The heat of neutralization remains constant. 5. **Conclusion**: - Therefore, even when mixing 250 cm³ of each liquid, the temperature rise will still be 5°C. ### Final Answer: The temperature rise when 250 cm³ of strong acid is mixed with 250 cm³ of strong base will be **5°C**.
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