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Ammonia gas dissolves in water to form N...

Ammonia gas dissolves in water to form `NH_(4)OH`. In this reaction water acts as

A

An acid

B

A base

C

A salt

D

A conjugate base

Text Solution

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The correct Answer is:
To determine how water acts in the reaction where ammonia gas dissolves in water to form NH₄OH, we can analyze the reaction step by step. ### Step 1: Write the Reaction When ammonia (NH₃) dissolves in water (H₂O), it forms ammonium hydroxide (NH₄OH). The reaction can be represented as: \[ \text{NH}_3(g) + \text{H}_2\text{O}(l) \rightleftharpoons \text{NH}_4^+(aq) + \text{OH}^-(aq) \] ### Step 2: Identify the Species Involved In this reaction: - NH₃ is the ammonia gas. - H₂O is water. - NH₄⁺ is the ammonium ion. - OH⁻ is the hydroxide ion. ### Step 3: Analyze the Role of Water In the reaction, water (H₂O) donates a proton (H⁺) to ammonia (NH₃). This donation of a proton leads to the formation of the ammonium ion (NH₄⁺) and the hydroxide ion (OH⁻). ### Step 4: Classify the Role of Water Since water donates a proton (H⁺) to ammonia, it acts as an acid in this reaction. According to the Brønsted-Lowry theory of acids and bases, an acid is defined as a substance that donates protons. ### Conclusion Thus, in the reaction where ammonia gas dissolves in water to form NH₄OH, water acts as an acid. ### Final Answer Water acts as an acid in this reaction. ---
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The dissolution of ammonia gas in water does not obey Henry's law. On dissolving. a major portion of ammonia molecules unite with H_(2),O to form NH_(4),OH molecules. A portion of the latter again dissociates into NH_(4)^(+) , and OH^(-) ions. In solution thercfore, we have NH_(3) , molecules, NH_(4),OH molecules and NH_(4)^(+) , ions and the following equilibrium exist: NH_(3(g)) (pressure P and concentration c) rarr NH_(3(l)) + H_(2),Orarr NH_(4),OH rarr NH_(4)^(+) rarr,+OH^(-) Let c_(1) ,mol/L of NH_(3) , pass in liquid state which on dissolution in water forms c_(2) mol/ L of NH_(4),OH. The solution contains c_(3) mol/L of NH_(4)^(+) , ions. If P is the partial pressure of ammonia at equilibrium, then which of the following is constant?

The dissolution of ammonia gas in water does not obey Henry's law. On dissolving. a major portion of ammonia molecules unite with H_(2),O to form NH_(4),OH molecules. A portion of the latter again dissociates into NH_(4)^(+) , and OH^(-) ions. In solution thercfore, we have NH_(3) , molecules, NH_(4),OH molecules and NH_(4)^(+) , ions and the following equilibrium exist: NH_(3(g)) (pressure P and concentration c) rarr NH_(3(l)) + H_(2),Orarr NH_(4),OH rarr NH_(4)^(+) rarr,+OH^(-) Let c_(1) ,mol/L of NH_(3) , pass in liquid state which on dissolution in water forms c_(2) mol/ L of NH_(4),OH. The solution contains c_(3) mol/L of NH_(4)^(+) , ions. Total concentration of undissociated ammonium hydroxide is