Home
Class 12
PHYSICS
As shown in the figure, a battery of emf...

As shown in the figure, a battery of emf `epsilon` is connected to an inductor L and resistance R in series. The switch is closed at t=0 . The total charge that flows from the battery, between `t=t_e` and `t=2t_e` (`t_e` is the time constant of the circuit) is:

A

`(epsilonL)/(R^2)(1-1/e)`

B

`(epsilonL)/(R^2)(1+1/e^2-1/e)`

C

`(epsilonL)/(R^2)(1+2/e^2-1/e)`

D

`(epsilonL)/(eR^2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`i=i_(0)(1-e^(Rt//L))=i_(0)(1-e^(-t//t_(c)))`
`q=int_(t_c)^(2t_c)"i dt "=int_(t_c)^(2t_c)(epsilon)/R(1-e^(-t//t_c))dt =(epsilonL)/(R^2)(1+1/e^2-1/e)`
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 7

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • MOCK TEST 6

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

  • MOCK TEST 8

    VMC MODULES ENGLISH|Exercise PHYSICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

As shown in the figure, a battery of emf is connected to an inductor L and resistance R in series. The switch is closed at . The total charge that flows from the battery, between t=t_e and t=2t_e ( t_e is the time constant of the circuit) is:

As shown in the figur a battery of emf in is conneced to an inductor L and resistance R in series . The swith is closed at t =0 . The total charge that flows form the battery between t 0 and t= t_(c) ( t_(c) is the time constant of the circuit )is :

The figure below shows a battery of emf epsilon connected to an inductor L and resistance R in series. If the switch is closed at t=0, then the total charge that flows from the battery in time constant of the circuit is

Two inductors are connected in parallel and switch S is closed at t=0

Consider the LR circuit shown in the figure. If the switch S is closed at t = 0 then the amount of charge that passes through the battery between t=0 and t=L/R is

In the circuit shown, the switch 'S' is closed at t = 0 . Then the current through the battery steady state reached is

The switch shown in figure is closed at t=0 find the charge throuh battery till time t=(L)/(R)

The switch shown in figure is closed at t=0 find the charge throuh battery till time t=(L)/(R)

Calculate the ratio of current flowing through the battery at t = 0 and t =oo (t = 0 is the time of closing of the switch)

An uncharged capacitor of capacitance C is connected with a battery of EMF V and a resistance R. The switch is closed at t=0 . The time instant at which the current in the circuit is (V)/(4R) is t=