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A uniform circular disc of radius a is t...

A uniform circular disc of radius a is taken. A circular portion of radius b has been removed from it as shown in the figure. If the center of hole is at a distance c from the center of the disc, the distance `x_(2)` of the center of mass of the remaining part from the initial center of mass O is given by

A

`(pi b^(2))/((a^(2)-b^(2)))`

B

`(-cb^(2))/((a^(2)-b^(2)))`

C

`(pic^(2))/((a^(2)-b^(2)))`

D

`(pia^(2))/((c^(2)-b^(2)))`

Text Solution

Verified by Experts

The correct Answer is:
B
`X_(cm)=(Mx-m_(1)x_(1))/(M-m_(1))=(sigma a^(2)(0)-sigma pib^(2)(c ))/(sigmapia^(2)-sigmapib^(2)) " "X_(cm)=(-cb^(2))/((a^(2)-b^(2)))`
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