Home
Class 12
MATHS
The area of the region enclosed by ...

The area of the region enclosed by ` x ^ 2 + y ^ 2 = 2 , y ^ 2 = x ` and y - axis is

A

`(pi)/4+1/3`

B

`(pi)/2+1/3`

C

`(pi)/4-1/3`

D

`(pi)/2-1/3`

Text Solution

Verified by Experts

The correct Answer is:
D

`x^2+y^2=2 , y^2=x`
Area=2 `int_0^1 y^2dy+2 int_0^sqrt2 sqrt(2-y^2)dy`
`=[2/3 y^3]_0^1 +[ ysqrt(2-y^2)+2 sin^(-1) y/sqrt2]_1^sqrt2`
`=2/3 + [pi-(1+pi/2)]=pi/2-1/3` Area = `pi/2 -1/3`
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 10

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • MOCK TEST 1

    VMC MODULES ENGLISH|Exercise PART III : MATHEMATICS (SECTION-2)|10 Videos
  • MOCK TEST 11

    VMC MODULES ENGLISH|Exercise MATHEMATICS (Section-2)|5 Videos

Similar Questions

Explore conceptually related problems

The area of the region enclosed by y=x^2 and y=sqrt(|x|) is

Find the area of the region enclosed by the curves y=x^(2) and y = 2x

The area of the region enclosed by the curve |y|=-(1-|x|)^2+5, is

The area of the region described by A = {(x,y) : x^2 + y^2 lt= 1and y^2 lt= 1- x} is

Find the area of the region enclosed by the parabola x^2=y , the line y" "=" "x" "+" "2 and the x-axis.

Find the area of the region enclosed by the curves y=x^(2) and y=x^(3)

Find area of region bounded by y = x^2 – 3x + 2, x = 1, x = 2 and y = 0 .

Find the area of the region bounded by x^2=4y , y = 2, y = 4 and the y-axis in the first quadrant.

Find the area of the region bounded by x^2=4y , y = 2, y = 4 and the y-axis in the first quadrant.

Find the area of the region enclosed by the parabola y=x^(2) + 2 , the lines y= -x, x= 0 and x=1