Home
Class 12
MATHS
If y=mx+6 is a tangent to both the para...

If y=mx+6 is a tangent to both the parabolas `y^2=8x` and `x^2=3by` , then b is equal to :

A

36

B

`-36`

C

`72`

D

`-72`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( b \) such that the line \( y = mx + 6 \) is a tangent to both parabolas \( y^2 = 8x \) and \( x^2 = 3by \). ### Step 1: Identify the parameters of the first parabola The equation of the first parabola is \( y^2 = 8x \). We can rewrite this in the standard form \( y^2 = 4ax \) where \( a = 2 \) (since \( 4a = 8 \)). ### Step 2: Use the tangent formula for the first parabola For the parabola \( y^2 = 4ax \), the equation of the tangent line can be expressed as: \[ y = mx + \frac{a}{m} \] Substituting \( a = 2 \): \[ y = mx + \frac{2}{m} \] Since we know the tangent line is also given by \( y = mx + 6 \), we can equate the two expressions: \[ \frac{2}{m} = 6 \] ### Step 3: Solve for \( m \) From the equation \( \frac{2}{m} = 6 \), we can solve for \( m \): \[ 2 = 6m \implies m = \frac{2}{6} = \frac{1}{3} \] ### Step 4: Write the equation of the tangent line Now that we have \( m \), we can write the equation of the tangent line: \[ y = \frac{1}{3}x + 6 \] ### Step 5: Substitute into the second parabola Next, we need to check if this line is also a tangent to the second parabola \( x^2 = 3by \). We can express \( y \) in terms of \( x \): \[ y = \frac{1}{3}x + 6 \] Substituting this into the parabola's equation: \[ x^2 = 3b\left(\frac{1}{3}x + 6\right) \] This simplifies to: \[ x^2 = bx + 18b \] ### Step 6: Rearrange the equation Rearranging gives us: \[ x^2 - bx - 18b = 0 \] ### Step 7: Use the discriminant condition for tangency For the line to be a tangent to the parabola, the discriminant of this quadratic equation must be zero: \[ D = b^2 - 4ac = 0 \] Here, \( a = 1 \), \( b = -b \), and \( c = -18b \): \[ D = (-b)^2 - 4(1)(-18b) = b^2 + 72b \] Setting the discriminant to zero: \[ b^2 + 72b = 0 \] ### Step 8: Factor the equation Factoring gives: \[ b(b + 72) = 0 \] This gives us two solutions: 1. \( b = 0 \) 2. \( b = -72 \) ### Step 9: Conclusion Since we are looking for the value of \( b \) that satisfies the conditions of the problem, we take: \[ b = -72 \] ### Final Answer Thus, the value of \( b \) is \( \boxed{-72} \).

To solve the problem, we need to find the value of \( b \) such that the line \( y = mx + 6 \) is a tangent to both parabolas \( y^2 = 8x \) and \( x^2 = 3by \). ### Step 1: Identify the parameters of the first parabola The equation of the first parabola is \( y^2 = 8x \). We can rewrite this in the standard form \( y^2 = 4ax \) where \( a = 2 \) (since \( 4a = 8 \)). ### Step 2: Use the tangent formula for the first parabola For the parabola \( y^2 = 4ax \), the equation of the tangent line can be expressed as: \[ ...
Promotional Banner

Topper's Solved these Questions

  • MOCK TEST 11

    VMC MODULES ENGLISH|Exercise MATHEMATICS (Section-2)|5 Videos
  • MOCK TEST 10

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos
  • MOCK TEST 12

    VMC MODULES ENGLISH|Exercise MATHEMATICS (SECTION 2)|5 Videos

Similar Questions

Explore conceptually related problems

If y=mx+4 is common tangent to parabolas y^(2)=4x and x^(2)=2by . Then value of b is

The common tangent of the parabolas y^(2)=4x" and "x^(2)=-8y, is

If y = mx + 1 is tangent to the parabola y = 2 sqrt(x) , then find the value of m

If y=2x-3 is tangent to the parabola y^2=4a(x-1/3), then a is equal to (a) (22)/3 (b) -1 (c) (14)/3 (d) (-14)/3

If y=2x-3 is tangent to the parabola y^2=4a(x-1/3), then a is equal to (22)/3 (b) -1 (c) (14)/3 (d) (-14)/3

If the line y = mx + 4 is tangent to x^(2) + y^(2) = 4 and y^(2) = 4ax then a is (a gt 0) equal to :

If the line y = mx + 4 is tangent to x^(2) + y^(2) = 4 and y^(2) = 4ax then a is (a gt 0) equal to :

If y=2x+3 is a tangent to the parabola y^2=24 x , then find its distance from the parallel normal.

If y=2x+3 is a tangent to the parabola y^2=24 x , then find its distance from the parallel normal.

The equation of tangent at (8,8) to the parabola y^2=8x is ?