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If f:[1,oo) to [2, oo)" is given by " f(...

If `f:[1,oo) to [2, oo)" is given by " f(x)=x+(1)/(x), " then " f^(-1)(x)` equals

A

`(x+sqrt(x^(2)-4))/(2)`

B

`(x)/(1+x^(2))`

C

`(x-sqrt(x^(2)-4))/(2)`

D

`1+sqrt(x^(2)-4)`

Text Solution

Verified by Experts

The correct Answer is:
A

Clearly, `f:[1,oo] to [2,oo]` is a bijection.
Let f(x)=y. Then,
f(x)=y
`Rightarrow x+(1)/(x)=y`
`Rightarrow x^(2)-xy+1=0`
`Rightarrow x^(2)-xy+1=0`
`Rightarrow x=(y+sqrt(y^(2)-4))/(2)" "[therefore x ge 1]`
`Rightarrow f^(-1)(y)=(y+sqrt(y^(2)-4))/(2)`
`"Hence," f^(-1)(x)=(x+sqrt(x^(2)-4))/(2)"for all "x in[1,oo]`
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