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"Let " I(n)=int tan^(n)x dx,(n gt 1). I(...

`"Let " I_(n)=int tan^(n)x dx,(n gt 1). I_(4)+I_(6)=a tan^(5)x+bx^(5)+C, " where C is a constant of integration, then the ordered pair (a,b) is equal to "`

A

`((1)/(5),-1)`

B

`(-(1)/(5),0)`

C

`(-(1)/(5),1)`

D

`((1)/(5),0)`

Text Solution

Verified by Experts

The correct Answer is:
d
We have , `:. I_(4)+I_(6)=inttan^(4)dx+inttan^(6)x dx`
`rArr I_(4)+I_(6)=int(tan^(4)x+tan^(6)x)dx`
`rArrI_(4)+I_(6)=inttan^(4)x(1+tan^(2)x)dx`
`rArr I_(4)+I_(6)=inttan^(4)xsec^(2)xdx =inttan^(4)xd (tanx)`
`rArrI_(4)+I_(6)=(1)/(5)tan^(5)x+C`
But, `I_(4)+I_(6)=atan^(5)x+bx^(5)+C`
`:. a=(1)/(5),b=0`
Hence , `( a ,b)=((1)/(5),0)`
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OBJECTIVE RD SHARMA ENGLISH-INDEFINITE INTEGRALS-Chapter Test
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  2. The integral int (2x-3)/(x^2+x+1)^2 .dx is equal to

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  3. If int(xtan^(-1)x)/sqrt(1+x^(2))dx = sqrt(1+x^(2))f(x) + A " ln "sqrt(...

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  4. "If " int xlog(1+1//x)dx=f(x)log(x+1)+g(x)x^(2)+Ax+C, then

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  5. If int(xe^(x))/(sqrt(1+e^(x)))dx=f(x)sqrt(1+e^(x))-2logg(x)+C, then

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  6. The value of int (cos^3x+cos^5)/(sin^2x+sin^4x)dx

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  7. If int(dx)/((x^(2)+1)(x^(2)+4))=k tan^(-1) x + l tan^(-1) . (x)/(2) +C...

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  8. If int log(sqrt(1-x)+sqrt(1+x))dx=xf(x)+Ax+Bsin^(-1)x+C, then

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  9. If int(x^(5))/(sqrt(1+x^(3)))dx is equal to

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  10. The value of : inte^(secx).sec^(3)x(sin^(2)x+cosx+sinx+sinxcosx)dx i...

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  11. If int(2x^(2)+3)/((x^(2)-1)(x^(2)+4))dx=aln((x-1)/(x+1))+btan^(-1).(x)...

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  12. Let f(x)=(x)/((1+x^(n))^(1//n)) for n ge 2 and g(x)=underset("n times"...

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  13. The value of int ((ax^(2)-b)dx)/(xsqrt(c^(2)x^(2)-(ax^(2)+b)^(2))) is ...

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  14. Evalaute: inte^(x)(1+nx^(n-1)-x^(2n))/((1-x^(n))sqrt(1-x^(2n))dx

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  15. int(xcosx+1)/(sqrt(2x^(3)e^(sinx)+x^(2)))dx

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  16. int(x^(3))/((1+x^(2))^(1//3))dx is equal to

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  17. int sinx/sin(x-alpha)dx=Ax+B log (sin(x-alpha))+C then find out (A ,B)

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  18. What is int (x^(2) +1)/(x^(4) - x^(2) + 1) dx equal to ?

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  19. Evaluate: int(x-1)/((x+1)sqrt(x^3+x^2+x))dx

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  20. int(1+x^(2))/(xsqrt(1+x^(4)))dx is equal to

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  21. int(1+x^(4))/((1-x^(4))^(3//2))dx is equal to

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