Home
Class 12
MATHS
Statement-1: Tangents drawn from any poi...

Statement-1: Tangents drawn from any point on the circle `x^(2)+y^(2)=225` to the ellipse `(x^(2))/(144)+(y^(2))/(81)=1` are at a right angle.
Statement -2 : Equation of the auxiliary circle of the ellipse `(x^(2))/(a^(2))+(y^(2))/(b^(2))=1 " is " x^(2)+y^(2)=a^(2)`.

A

Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is True, Statement-2 is True, Statement -2 is not a correct explanation for Statement-1

C

Statement-1 is True, Statement-2 is False.

D

Statement-1 is False, Statement-2 is True

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given statements regarding the tangents drawn from a point on the circle to the ellipse, we will analyze both statements step by step. ### Step 1: Analyze Statement 1 **Statement 1:** Tangents drawn from any point on the circle \(x^2 + y^2 = 225\) to the ellipse \(\frac{x^2}{144} + \frac{y^2}{81} = 1\) are at a right angle. 1. **Identify the Circle and Ellipse:** - The circle has the equation \(x^2 + y^2 = 225\), which means it has a radius of \(15\) (since \(15^2 = 225\)). - The ellipse has the equation \(\frac{x^2}{144} + \frac{y^2}{81} = 1\), where \(a^2 = 144\) and \(b^2 = 81\). Thus, \(a = 12\) and \(b = 9\). 2. **Determine the Director Circle of the Ellipse:** - The equation of the director circle for the ellipse is given by: \[ x^2 + y^2 = a^2 + b^2 \] - Substituting the values of \(a^2\) and \(b^2\): \[ a^2 + b^2 = 144 + 81 = 225 \] - Therefore, the equation of the director circle is: \[ x^2 + y^2 = 225 \] 3. **Conclusion for Statement 1:** - Since the circle \(x^2 + y^2 = 225\) is the same as the director circle of the ellipse, tangents drawn from any point on this circle to the ellipse will indeed be at right angles. Thus, Statement 1 is **true**. ### Step 2: Analyze Statement 2 **Statement 2:** The equation of the auxiliary circle of the ellipse \(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) is \(x^2 + y^2 = a^2\). 1. **Understanding the Auxiliary Circle:** - The auxiliary circle of an ellipse is defined as the circle that has the same center as the ellipse and a radius equal to the semi-major axis \(a\). - The equation of the auxiliary circle is: \[ x^2 + y^2 = a^2 \] - This is correct as it represents a circle centered at the origin with radius \(a\). 2. **Conclusion for Statement 2:** - Since the definition and equation provided in Statement 2 are accurate, Statement 2 is also **true**. ### Final Conclusion - Both Statement 1 and Statement 2 are true. However, Statement 2 does not provide a correct explanation for Statement 1, as they refer to different concepts (director circle vs. auxiliary circle). ### Answer: - **Option B:** Statement 1 is true, Statement 2 is true, but Statement 2 is not a correct explanation of Statement 1.

To solve the given statements regarding the tangents drawn from a point on the circle to the ellipse, we will analyze both statements step by step. ### Step 1: Analyze Statement 1 **Statement 1:** Tangents drawn from any point on the circle \(x^2 + y^2 = 225\) to the ellipse \(\frac{x^2}{144} + \frac{y^2}{81} = 1\) are at a right angle. 1. **Identify the Circle and Ellipse:** - The circle has the equation \(x^2 + y^2 = 225\), which means it has a radius of \(15\) (since \(15^2 = 225\)). - The ellipse has the equation \(\frac{x^2}{144} + \frac{y^2}{81} = 1\), where \(a^2 = 144\) and \(b^2 = 81\). Thus, \(a = 12\) and \(b = 9\). ...
Promotional Banner

Topper's Solved these Questions

  • ELLIPSE

    OBJECTIVE RD SHARMA ENGLISH|Exercise Exercise|80 Videos
  • ELLIPSE

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|29 Videos
  • ELLIPSE

    OBJECTIVE RD SHARMA ENGLISH|Exercise Section I - Solved Mcqs|59 Videos
  • DIFFERENTIATION

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|30 Videos
  • EXPONENTIAL AND LOGARITHMIC SERIES

    OBJECTIVE RD SHARMA ENGLISH|Exercise Chapter Test|20 Videos

Similar Questions

Explore conceptually related problems

Statement-1: Tangents drawn from any point on the circle x^(2)+y^(2)=25 to the ellipse (x^(2))/(16)+(y^(2))/(9)=1 are at right angle Statement-2: The locus of the point of intersection of perpendicular tangents to an ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is its director circle x^(2)+y^(2)=a^(2)+b^(2) .

If tangents are drawn from any point on the circle x^(2) + y^(2) = 25 the ellipse (x^(2))/(16) + (y^(2))/(9) =1 then the angle between the tangents is

Tangents are drawn from any point on the circle x^(2)+y^(2) = 41 to the ellipse (x^(2))/(25)+(y^(2))/(16) =1 then the angle between the two tangents is

The equation to the auxiliary circle of (x^(2))/(7)+(y^(2))/(5)=1 is

Angle between tangents drawn from any point on the circle x^2 +y^2 = (a + b)^2 , to the ellipse x^2/a+y^2/b=(a+b) is-

The equation of the auxiliary circle of x^(2)/(16)-y^(2)/(25)=1 is

The angle between the tangents drawn from a point on the director circle x^(2)+y^(2)=50 to the circle x^(2)+y^(2)=25 , is

Two tangents are drawn from a point on hyperbola x^(2)-y^(2)=5 to the ellipse (x^(2))/(9)+(y^(2))/(4)=1 . If they make angle alpha and beta with x-axis, then

The locus of the poles of tangents to the auxiliary circle with respect to the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 , is

Tangents drawn from a point on the circle x^2+y^2=9 to the hyperbola x^2/25-y^2/16=1, then tangents are at angle