The density of a solution containing 13% by mass of sulphuric acid is 1.09 g/mL. Calculate the normality of the solution.

Explanation

Volume of 100 g of the solution
`=100/d = 100/1.09 mL`
Normality `= (wxx1000)/(ExxV)`
`w= 13 g " in " 100 g`
`V=100/1.09 mL`
`E = 98//2 = 49 ("Basicity of " H_2SO_4` is 2)
`N = (13xx1000 xx1.09)/(49xx100)=2.89`
Normality = 2.89 N