0.90 g of a non-electrolyte was dissolved in 87.90 g of benzene. This raised the boiling point of benzene by `0.25 ^@C` . If the molecular mass of the non-electrolyte is `103.0 g mol^(-1)`, calculate the molal elevation constant for benzene.

Explanation

Molal elevation constant,
`DeltaT_b = (K_bxx1000xxw_B)/(W_A xxm_B) or K_b (DeltaT_bxx W_Axx m_B)/(1000xxw_B)`
`m_B = 103.0 g mol^(-1), W_A=87.90 g`,
`W_B=0.90 g, DeltaT_b = 0.25 ^@C`
`K_b = (0.25 xx103xx 87.90)/(1000 xx0.90) = 2.515 Km^(-1)`