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if x[{:(2),(3):}]+y[{:(-1),(5):}]=[{:(4)...

`if x[{:(2),(3):}]+y[{:(-1),(5):}]=[{:(4),(19):}],`then the values of `x` and `y` are:

A

`x=y,y=3`

B

`x=6,y=8`

C

`x=3,y=2`

D

None of these

Text Solution

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The correct Answer is:
To solve the equation \( x \begin{pmatrix} 2 \\ 3 \end{pmatrix} + y \begin{pmatrix} -1 \\ 5 \end{pmatrix} = \begin{pmatrix} 4 \\ 19 \end{pmatrix} \), we will follow these steps: ### Step 1: Set up the equations We can express the equation in terms of its components: 1. From the first row: \( 2x - y = 4 \) (Equation 1) 2. From the second row: \( 3x + 5y = 19 \) (Equation 2) ### Step 2: Solve Equation 1 for \( y \) From Equation 1, we can express \( y \) in terms of \( x \): \[ y = 2x - 4 \] ### Step 3: Substitute \( y \) in Equation 2 Now, we substitute \( y \) in Equation 2: \[ 3x + 5(2x - 4) = 19 \] Expanding this gives: \[ 3x + 10x - 20 = 19 \] Combining like terms: \[ 13x - 20 = 19 \] ### Step 4: Solve for \( x \) Now, we isolate \( x \): \[ 13x = 19 + 20 \] \[ 13x = 39 \] \[ x = \frac{39}{13} = 3 \] ### Step 5: Substitute \( x \) back to find \( y \) Now that we have \( x \), we can find \( y \) using the expression we derived in Step 2: \[ y = 2(3) - 4 \] \[ y = 6 - 4 = 2 \] ### Final Answer Thus, the values of \( x \) and \( y \) are: \[ x = 3, \quad y = 2 \] ---

To solve the equation \( x \begin{pmatrix} 2 \\ 3 \end{pmatrix} + y \begin{pmatrix} -1 \\ 5 \end{pmatrix} = \begin{pmatrix} 4 \\ 19 \end{pmatrix} \), we will follow these steps: ### Step 1: Set up the equations We can express the equation in terms of its components: 1. From the first row: \( 2x - y = 4 \) (Equation 1) 2. From the second row: \( 3x + 5y = 19 \) (Equation 2) ### Step 2: Solve Equation 1 for \( y \) ...
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