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If (x, y), (a, 0), (0, b) are collinear,...

If `(x, y), (a, 0), (0, b)` are collinear, then using determinants prove that `x/a + y/b = 1` .

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Statement -1 : If veca and vecb are non- collinear vectors, then points having position vectors x_(1) vec(a) + y_(1) vec(b) , x_(2)vec(a)+ y_(2) vec(b) and x_(3) veca + y_(3) vecb are collinear if |(x_(1),x_(2),x_(3)),(y_(1),y_(2),y_(3)),(1,1,1)|=0 Statement -2: Three points with position vectors veca, vecb , vec c are collinear iff there exist scalars x, y, z not all zero such that x vec a + y vec b + z vec c = vec 0, " where " x+y+z=0.

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Show that the points (a,0),(0,b) and (x,y) are collinear if x/a+y/b=1.