Home
Class 12
MATHS
The area of the region bounded by the c...

The area of the region bounded by the curve `y=x"sin"x,` x-axis, `x=0` and `x=2pi` is :

A

`2pi` sq. units

B

`3pi` sq. units

C

`4pi` sq. units

D

`5pi` sq. units

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8.1|13 Videos
  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8.2|7 Videos
  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8 B Multiple Choice Questions|10 Videos
  • APPLICATIONS OF DERIVATIVES

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|24 Videos
  • Continuity and Differentiability

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|23 Videos

Similar Questions

Explore conceptually related problems

Find the area of that region bounded by the curve y="cos"x, X-axis, x=0 and x=pi .

The area of the region bounded by the curve y="sin"2x, y-axis and y=1 is :

If f(x) = max {sin x, cos x,1/2}, then the area of the region bounded by the curves y =f(x), x-axis, Y-axis and x=(5pi)/3 is

The area of the region bounded by the curves y=|x-1|andy=3-|x| is

The area of the region bounded by the curve y= 2x -x^(2) and x - axis is

Find the area of the region bounded by the curve y = sin x between x = 0 and x= 2pi .

Let f(x)="max"{sin x,cos x,1/2} , then determine the area of region bounded by the curves y=f(x) , X-axis, Y-axis and x=2pi .

The area of the region bounded by the curves y=x^(2)+2,y=x,x= 0 andx=3 is

The area of the region bounded by the curve y = "sin" x between the ordinates x=0 , x=pi/2 and the X-"axis" is

Find the area of the region bounded by the curve y="sin"x,x=(pi)/(2)andx=(3pi)/(2)