Home
Class 12
MATHS
The area of the region bounded by the cu...

The area of the region bounded by the curve `y="sin"2x,` y-axis and `y=1` is :

A

1 sq. unit

B

`(1)/(2)` sq. unit

C

`(1)/(4)` sq. unit

D

`((pi)/(4)-(1)/(2))` sq. uint

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8.1|13 Videos

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8.2|7 Videos

  • APPLICATIONS OF INTEGRALS

    NAGEEN PRAKASHAN ENGLISH|Exercise Exercise 8 B Multiple Choice Questions|10 Videos

  • APPLICATIONS OF DERIVATIVES

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|24 Videos

  • Continuity and Differentiability

    NAGEEN PRAKASHAN ENGLISH|Exercise Miscellaneous Exercise|23 Videos

Similar Questions

Explore conceptually related problems

The area of the region bounded by the curve y=x"sin"x, x-axis, x=0 and x=2pi is :

The area bounded by the curve y = sin2x, axis and y=1, is

Find the area of that region bounded by the curve y="cos"x, X-axis, x=0 and x=pi .

The area of the region bounded by the curves y=|x-1|andy=3-|x| is

The area of the region bounded by the curve y=x^(3) , X-axis and the ordinates x = 1, x = 4 is

The area of the region bounded by the curve y = |x - 1| and y = 1 is:

Find by integration the area of the region bounded by the curve y=2x-x^2 and the x-axis.

Find by integration the area of the region bounded by the curve y=2x-x^2 and the x-axis.

The area of the region bounded by the curve y= 2x -x^(2) and x - axis is

Find the area of the region bounded by the curve y= x^(2)-2x , the x-axis and the lines x=1 and x= -1