Find the general solution of the differential equation `y dx-(x+2y^2)dy=0`.

Explanation

`ydx+(x-y^(2))dy=0implies(dx)/(dy)+(1)/(y)x=y`
Here, `P=(1)/(y)`, `Q=y`
`:. I.F. =e^(int(1)/(y)dy)=e^(logy)=y`
and general solution :
`x(y)=inty(y)dy+cimpliesxy=(y^(3))/(3)+c`
`implies 3xy=y^(3)+3c`
`implies 3xy=y^(3)+c_(1)` where `c_(1)=3c`