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(i) Find the number of terms in the A.P....

(i) Find the number of terms in the A.P.
8, 12, 16, ........124
(ii) Find the number of terms in the A.P.
75, 70, 65, .....15

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To solve the problem, we need to find the number of terms in two arithmetic progressions (A.P.). ### Part (i): Find the number of terms in the A.P. 8, 12, 16, ..., 124 1. **Identify the first term (A)**: - The first term \( A = 8 \). 2. **Find the common difference (D)**: - The common difference \( D = 12 - 8 = 4 \). 3. **Identify the last term (An)**: - The last term \( An = 124 \). 4. **Use the formula for the nth term of an A.P.**: - The formula is given by: \[ An = A + (n - 1)D \] - Substitute the known values into the formula: \[ 124 = 8 + (n - 1) \cdot 4 \] 5. **Simplify the equation**: - Rearranging gives: \[ 124 = 8 + 4n - 4 \] - This simplifies to: \[ 124 = 4 + 4n \] 6. **Isolate the term with n**: - Subtract 4 from both sides: \[ 120 = 4n \] 7. **Solve for n**: - Divide both sides by 4: \[ n = \frac{120}{4} = 30 \] 8. **Conclusion**: - The number of terms in the A.P. is **30**. ### Part (ii): Find the number of terms in the A.P. 75, 70, 65, ..., 15 1. **Identify the first term (A)**: - The first term \( A = 75 \). 2. **Find the common difference (D)**: - The common difference \( D = 70 - 75 = -5 \). 3. **Identify the last term (An)**: - The last term \( An = 15 \). 4. **Use the formula for the nth term of an A.P.**: - The formula is: \[ An = A + (n - 1)D \] - Substitute the known values into the formula: \[ 15 = 75 + (n - 1)(-5) \] 5. **Simplify the equation**: - Rearranging gives: \[ 15 = 75 - 5n + 5 \] - This simplifies to: \[ 15 = 80 - 5n \] 6. **Isolate the term with n**: - Subtract 80 from both sides: \[ -65 = -5n \] 7. **Solve for n**: - Divide both sides by -5: \[ n = \frac{65}{5} = 13 \] 8. **Conclusion**: - The number of terms in the A.P. is **13**. ### Summary of Answers: - (i) The number of terms in the A.P. 8, 12, 16, ..., 124 is **30**. - (ii) The number of terms in the A.P. 75, 70, 65, ..., 15 is **13**.
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NAGEEN PRAKASHAN ENGLISH-ARITHMETIC PROGRESSION-Exercise 5b
  1. (a) Find the 10th term of the progression 1 + 3 + 5 +7+ ... (b) Fin...

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  2. (i) Which term of the A.P. 4, 8, 12, ...... Is 76? (ii) Which term o...

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  3. (i) Find the number of terms in the A.P. 8, 12, 16, ........124 (i...

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  4. (a) How many numbers of two digits are divisible by 3 ? (b) How man...

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  5. (i)Which term of the A.P. 4, 3(5)/(7), 3(3)/(7), ..... is the first ne...

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  6. The 18th term of an A.P. exceeds its 12th term by 24. Find the common ...

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  7. Is 313, a term of the A.P. 5, 10, 15, ..... ?

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  8. (i) The 3rd and 19th terms of an A.P. are 13 and 17 respectively. Find...

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  9. (i) 6 times the 6th term of an A.P. is equal to 10 times the 10th term...

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  10. If (m+1)^(t h) term of an A.P. is twice the (n+1)^(t h) term, prove th...

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  11. Which term of the arithmetic progression 5,\ 15 ,\ 25 ,\ dot will b...

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  12. Find the value of k if k+1, 2k+1 and k+7 are in A.P.. Also find the ne...

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  13. Determine k, so that k^(2)+4k+8, 2k^(2)+3k+6 and 3k^(2)+4k+4 are three...

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  14. The p^(t h),q^(t h)and r^(t h)terms of an A.P. are a, b, c, respectiv...

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  15. The sequence p(1), p(2), p(3), ... satisfies the relation 2p(n)=p(n-1)...

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  16. (i) The nth term of a progression is 2n+1. Prove that it is an A. P. ...

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  17. (i) Find the 10th term from the end of the A.P. 82, 79, 76, .... , 4...

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  18. In a flower bed, therare 51 plants in the first row, 48 plants in th s...

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  19. Subba Rao started work in 1995 at an annual salary of Rs 5000 and r...

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  20. The salary of Karishma increases by Rs. 1000 every three months. If h...

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