Show that the function `f(x)=x^2+3x+5`,is continuos at x=1.

Explanation

To show that the function \( f(x) = x^2 + 3x + 5 \) is continuous at \( x = 1 \), we need to verify that:

1. The left-hand limit as \( x \) approaches 1 exists.
2. The right-hand limit as \( x \) approaches 1 exists.
3. The value of the function at \( x = 1 \) is equal to both the left-hand and right-hand limits.

### Step 1: Find the Right-Hand Limit

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