If `f(x)={(x^3+x^2-16x+20)/(x-2)^2,x ne 0`
k, x=0 is continuous for all real values of x, find the value of K.

Explanation

To find the value of \( k \) such that the function \( f(x) \) is continuous for all real values of \( x \), we need to ensure that the left-hand limit and right-hand limit at \( x = 0 \) are equal to \( f(0) \).

Given:
\[
f(x) =
\begin{cases}
\frac{x^3 + x^2 - 16x + 20}{(x-2)^2}, & x \neq 0 \\
k, & x = 0
...