If y=` tan ^-1((ax-b)/(bx+a)) " then prove that " dy/dx=1/(1+x^2).`

Explanation

To prove that if \( y = \tan^{-1}\left(\frac{ax - b}{bx + a}\right) \), then \( \frac{dy}{dx} = \frac{1}{1 + x^2} \), we can follow these steps:

### Step 1: Rewrite the Expression
Start with the given expression for \( y \):
\[ y = \tan^{-1}\left(\frac{ax - b}{bx + a}\right) \]

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