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If x=a t^2,\ \ y=2\ a t , then find (dy)...

If `x=a t^2,\ \ y=2\ a t` , then find `(dy)/(dx)`

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`x=at^2`
`rArr dy/dx =a.d/dt(t^2)=a.2t=2at` and y=2 at
`rArr dy/dx =2a.d/dt (t)=2a .(1)=2a`
Now `dy/dx=(dy//dt)/(dx//dt)=(2a)/(2 at) =1/t.`
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NAGEEN PRAKASHAN ENGLISH-Continuity and Differentiability-Miscellaneous Exercise
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