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If x=acos^(3) theta, y=a sin^(3) theta, ...

If `x=acos^(3) theta, y=a sin^(3) theta`, then `([1+((dy)/(dx))^(2)]^(3//2))/((d^(2)y)/(dx^(2)))` is equal to

A

`tan^(2) theta`

B

`sec ^(2) theta`

C

`sec theta`

D

`|sec theta|`

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The correct Answer is:
D
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