Evaluate : ` int x " sin"^(2) " x dx "`

Explanation

To evaluate the integral \( I = \int x \sin^2 x \, dx \), we can follow these steps:

### Step 1: Rewrite \(\sin^2 x\)
Using the identity \(\sin^2 x = \frac{1 - \cos 2x}{2}\), we can rewrite the integral:
\[ I = \int x \sin^2 x \, dx = \int x \cdot \frac{1 - \cos 2x}{2} \, dx = \frac{1}{2} \int x (1 - \cos 2x) \, dx \]

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