`int 2^(x) " dx "`

Answer

To solve the integral \( \int 2^x \, dx \), we can follow these steps:

### Step 1: Identify the integral
We start with the integral:
\[ I = \int 2^x \, dx \]

### Step 2: Use the integration formula for exponential functions
We know the formula for integrating \( a^x \):
\[ \int a^x \, dx = \frac{a^x}{\log(a)} + C \]
where \( a \) is a constant and \( C \) is the constant of integration.

### Step 3: Substitute \( a \) with 2
In our case, \( a = 2 \). Therefore, we can apply the formula:
\[ I = \frac{2^x}{\log(2)} + C \]

### Step 4: Write the final answer
Thus, the final answer for the integral is:
\[ \int 2^x \, dx = \frac{2^x}{\log(2)} + C \]

### Summary of the solution
The integral of \( 2^x \) with respect to \( x \) is:
\[ \int 2^x \, dx = \frac{2^x}{\log(2)} + C \]

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