`int sec^(2) " z dz "`

Answer

To solve the integral \( \int \sec^2 z \, dz \), we can follow these steps:

### Step 1: Identify the Integral
We start with the integral:
\[ I = \int \sec^2 z \, dz \]

### Step 2: Use the Known Formula
We know from calculus that the integral of \( \sec^2 z \) is a standard result. Specifically, we have:
\[ \int \sec^2 z \, dz = \tan z + C \]
where \( C \) is the constant of integration.

### Step 3: Write the Result
Thus, we can write:
\[ I = \tan z + C \]

### Final Answer
The solution to the integral \( \int \sec^2 z \, dz \) is:
\[ \tan z + C \]