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If f'(x) = 1/x + x^2 and f(1)=4/3 then f...

If `f'(x) = 1/x + x^2` and `f(1)=4/3` then find the value of `f(x)`

Text Solution

Verified by Experts

The correct Answer is:
`f(x) =log x+.(x^(3))/(3)+1`
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