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intcos(logx)dx is equal to (A) ...

`intcos(logx)dx` is equal to (A) `x/2(cos(logx)-sin(logx))+c` (B) `x(cos(logx)+sin(logx))+c` (C) `x/2(cos(logx)+sin(logx)+c` (D) `x(cos(logx)-sin(logx))+c`

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The correct Answer is:
B
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