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int (-1)^(1) (x+1)dx...

`int _(-1)^(1) (x+1)dx`

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To solve the integral \( I = \int_{-1}^{1} (x + 1) \, dx \), we will break it down step by step. ### Step 1: Set up the integral We start with the integral: \[ I = \int_{-1}^{1} (x + 1) \, dx \] ...
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