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Evaluate : int0^1 1/(1+x^2)dx...

Evaluate : `int_0^1 1/(1+x^2)dx`

Text Solution

Verified by Experts

`int_(0)^(1)(1)/(1+x^(2))dx=[tan^(-1)x]_(0)^(1)`
`=tan^(-1)1-tan^(-1)0=.(pi)/(4)`
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