Home
Class 12
MATHS
Statements (p to q) harr (~q to ~p)...

Statements `(p to q) harr (~q to ~p)`

A

is contradiction

B

is tautology

C

is neither contradiction not tautology

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`(~q to ~p)` is contrapositive of `(p to q)`
Therefore, `(pto q) harr(~q to ~p)` is tautology.
Promotional Banner

Topper's Solved these Questions

  • MATHMETICAL REASONING

    CENGAGE|Exercise JEE Previous Year|10 Videos

  • MATHMETICAL REASONING

    CENGAGE|Exercise Exercise 10.2|5 Videos

  • LOGARITHM AND ITS PROPERTIES

    CENGAGE|Exercise JEE Previous Year|5 Videos

  • MATRICES

    CENGAGE|Exercise Multiple Correct Answer|7 Videos

Similar Questions

Explore conceptually related problems

Consider : Statement I: (p^^~q)^^(~p^^q) is a fallacy Statement II: (ptoq)harr(~q to ~p) is a tautology

In the truth table for the statements ( p to q) harr(~p vvq) , the last column has the truth value in the following order

The following statement (p to q) to [(~p to q) to q] is

If each of the statements p to ~q , ~ r to q and p are true then which of the following is NOT true ?

Using truth table check whether the statements ~(p vee q) vee (~p wedge q) and ~p are logically equivalent.

If the statements (p^^~r) to (qvvr) , q and r are all false, then p

Which condictional statement p to q is equivalent to :

Which one is the inverse of the statement (p vee q) to (p wedge q) ?

Construct the truth table for the followings statements : (a) (p^^q) to ~ p " " (b) (p^^q) to (pvvq) (c) (p^^q) to r " " (d) [p^^(~r)] to (qvvr)

The statement pto(q to p) is equivalent to