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If log(10) x = y ," then find "log(1000...

If ` log_(10) x = y ," then find "log_(1000)x^(2)" in terms of " y`.

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The correct Answer is:
`2/3 y`
` log_(1000)(x^(2)) = 2/3 log_(10) x =- 2/3 y`
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