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There are 3 number a, b and c such that ...

There are 3 number a, b and c such that ` log_(10) a = 5.71, log_(10) b = 6.23 and log_(10) c = 7.89`. Find the number of digits before dicimal in ` (ab^(2))/c`.

Text Solution

Verified by Experts

The correct Answer is:
11
`N = (ab^(2))/c`
`:. Log_(10) N = log_(10) a+ 2log_(10) b - log_(10) c = 10.28`
So, characteristic of N is 10`.
So, number of digits before decimal is 11.
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