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("lim")(n->oo)sum(x=1)^(20)cos^(2n)(x-10...

`("lim")_(n->oo)sum_(x=1)^(20)cos^(2n)(x-10)` is equal to (a) 0 (b) 1 (c) 19 (d) 20

A

2

B

-2

C

1

D

-1

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(ntooo)limcos^(2n)x={{:(1", "x=rpi","r inl),(0", "xnerpi","r inl):}`
Here, for `x=10`, `underset(ntooo)limcos^(2n)(x-10)=1` and in all other cases, it is zero. Therefore,
`underset(ntooo)limsum_(x=1)^(oo)cos^(2n)(x-10)=1`
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  10. lim(xtooo) (1)/(x+1)tan((pix+1)/(2x+2)) is equal to

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  11. The value of ("lim")(xvec1^-)(1-sqrt(x))/((ccos^(-1)x)^2) is 4 (b) ...

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  19. ("lim")(xvecoo)(e^1//x^2-1)/(2tan^(-1)(x^2)-pi)i se q u a lto 1 (b) -...

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