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Let f(x) = (x^2-9x+20)/(x-[x]) where [x]...

Let `f(x) = (x^2-9x+20)/(x-[x])` where `[x]` denotes greatest integer less than or equal to `x`), then

A

-1

B

`1//2`

C

1

D

`3//2`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`underset(xto5^(-))lim(x^(2)-9x+20)/(x-[x])=underset(xto5^(-))lim((x-5)(x-4))/(x-4)=underset(xto5^(-))lim(x-5)=0`
`underset(xto5^(+))lim(x^(2)-9x+20)/(x-[x])=underset(xto5^(+))lim((x-5)(x-4))/(x-5)=underset(xto5^(+))lim(x-4)=1`
Hence , limit does not exist.
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