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Match the following :

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The correct Answer is:
`atoq;btor;ctoq;d to p.`

We know that `underset(xto0)lim(sinx)/(x)=1` (but a value is smaller than 1)
or `[underset(xto0)lim100(sinx)/(x)]=99`
and `[underset(xto0)lim100(x)/(sinx)]=100`
Also, `underset(xto0)lim(sin^(-1)x)/(x)=1" "`(but a value is more than 1)
or `[underset(xto0)lim100(sin^(-1)x)/(x)]=100`
and `[underset(xto0)lim100(x)/(sin^(-1)x)]=99`
`underset(xto0)lim(tanx)/(x)=1" "`(but a value is bigger than 1)
or `[underset(xto0)lim100(tanx)/(x)]=100`
and `[underset(xto0)lim100(tan^(-1)x)/(x)]=99`
Hence,
a. `underset(xto0)lim([100(sinx)/(x)]+[100(tanx)/(x)])=199`
b. `underset(xto0)lim([100(x)/(sinx)]+[100(tanx)/(x)])=200`
c. `underset(xto0)lim([100(sin^(-1)x)/(x)]+[100(tan^(-1)x)/(x)])=199`
d. `underset(xto0)lim([100(x)/(sin^(-1)x)]+[100(tan^(-1)x)/(x)])=198`
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